Studying the DC BIAS diagrams in the site I see that they use a resistor divisor to get the DC BIAS value. Trivial enough. But I don’t understand why are you using a capacitor to ground. Several explanations say that this is used to provide a ground for AC component but I don’t understand the explanation.
Yes, I understand that the capacitor is a open circuit for DC and a short circuit for AC (ideally) but I just don’t understand WHY is that needed at all.
I even see this schema in the OpAmp version, where it makes even less sense to me.
I have the feeling that I am missing something important.
Please, could you state the detailed reason for this?. I don’t understand the “it provides a ground for AC” explanation. I get the physical meaning but I don’t understand the reason why that is needed.
In fact, the interaction between the voltage divider and the inductor in the CT looks complicated and I don’t see any analysis about it. Thinking about it, this could be the exact reason for the capacitor, isolating the divider from the inductor, providing a low resistence path to avoid disturb the voltage divisor. There is a non trivial interaction, though.
Anyway, isolating the voltage divider from the CT seems a pretty good idea (via an OpAmp).
I don’t see either any overcurrent protection. That is, what happens if a 30A rated CT is measuring a 35A current. Apparently you would destroy the ADC pin in the chip and blow the capacitor if it has polarity (electrolytic). Could be that the magnetic core of the CT gets saturated and you are counting on that to protect you?.
I like to understand what I am doing instead of just cloning designs without any real understanding. I am engineer, although not in electronics :-). Have been 25 years since I did a SPICE simulation…
Thanks!.