It’s not an inline (series) resistor, it’s one in parallel. The internal burden for channels 1 - 3 is 22 Ω, for input 4 it is 120 Ω. So you need to add a parallel resistor to bring channel 4 down to 22 Ω - that’s 27 Ω. You will find the 120 Ω resistor and two holes suitable for your new wire-ended resistor just behind the channel 4 socket.

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