Hello @guidoism

There are a couple of similar threads that might be useful:

I did try to estimate heat output on a Midea split air to air heat pump a few years ago, but have not revisited in detail. These were the notes I took down at the time:

Test results:

  • Average power consumed by the heatpump in test: 670W
  • Average air out: 40.3C
  • Average air in: 22.7C
  • Delta T: 17.6K
  • Outside temperature: 17.3C

Air to air calcs:

heat_output_factor (W/K) = (fan_air_rate (m3/h)/3600) x air_density (kg/m3) x specific_heat (J/kgK)

deltaT = air out - air in

heat_output = heat_output_factor x deltaT

3 air rates in the datasheet: 600 m3/h, 500m3/h, 360 m3/h

heat_output_factor (W/K) @ 600 m3/h = (600÷3600)×1.204×1012 = 203 W/K

heat_output_factor (W/K) @ 500 m3/h = (500÷3600)×1.204×1012 = 169 W/K

heat_output_factor (W/K) @ 360 m3/h = (360÷3600)×1.204×1012 = 122 W/K

Running on full fan power ~600m3/h suggests heat output factor of~203W/K

Lets say ± 50m3/h so 550-650 m3/h fan speed to give us an error range

So heat output ~ 17.6K x 203 W/K (186-220) = 3573 W (±300W)

COP = 5.33 (4.9 - 5.8)


The problem with this is knowing the fan air rate accurately, especially on variable speed blower units…

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