Hello @guidoism
There are a couple of similar threads that might be useful:
I did try to estimate heat output on a Midea split air to air heat pump a few years ago, but have not revisited in detail. These were the notes I took down at the time:
Test results:
- Average power consumed by the heatpump in test: 670W
- Average air out: 40.3C
- Average air in: 22.7C
- Delta T: 17.6K
- Outside temperature: 17.3C
Air to air calcs:
heat_output_factor (W/K) = (fan_air_rate (m3/h)/3600) x air_density (kg/m3) x specific_heat (J/kgK)
deltaT = air out - air in
heat_output = heat_output_factor x deltaT
3 air rates in the datasheet: 600 m3/h, 500m3/h, 360 m3/h
heat_output_factor (W/K) @ 600 m3/h = (600÷3600)×1.204×1012 = 203 W/K
heat_output_factor (W/K) @ 500 m3/h = (500÷3600)×1.204×1012 = 169 W/K
heat_output_factor (W/K) @ 360 m3/h = (360÷3600)×1.204×1012 = 122 W/K
Running on full fan power ~600m3/h suggests heat output factor of~203W/K
Lets say ± 50m3/h so 550-650 m3/h fan speed to give us an error range
So heat output ~ 17.6K x 203 W/K (186-220) = 3573 W (±300W)
COP = 5.33 (4.9 - 5.8)
The problem with this is knowing the fan air rate accurately, especially on variable speed blower units…
1 Like